Question

Reduce the equation √3x + y+ 2 = 0 to the normal form.​

Answer 1

(i) Given:

√3x + y + 2 = 0 y = – √3x – 2 This is the slope intercept form of the given line. ∴ The slope = – √3 and y – intercept = -2

(ii) Given:

√3x + y + 2 = 0 √3x + y = -2 Divide both sides by -2, we get √3x/-2 + y/-2 = 1 ∴ The intercept form of the given line. Here, x – intercept = – 2/√3 and y – intercept = -2

(iii) Given:

√3x + y + 2 = 0 -√3x – y = 2

Hope it helps you....

Answer 2

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