Question

Reduce the equation of a circle to standard form
x²+y²-10x+8y-8=0
Find the center and the raduis?

Answer 1

Answer:

Please find the attached image.

Step-by-step explanation:

Answer 2

Answer:

The centre is (5,4) and radius r = 7

Explanation:

The given eqn. :x2+y2−10x−8y−8=0.

Completing squares on L.H.S., we get,

x2−10x+25+y2−8y+16=8+25+16=49.

∴(x−5)2+(y−4)2=72................(1)

Now the stamdard equation of a circle with centre (h,k) & radius=r is given by,

(x−h)2+(y−k)2=r2

Comparing (1) with the std. eqn, we find that,

the centre is (5,4), radius r = 7