Question

Reduce the equation of the plane any 2x-y+z=5 to intercept form
and find the intercepts on the coordinates axes.​

Answer 1

hey user !

Answer:

a = 5/2

b = -5

c = 5

Step-by-step explanation:

Equation of the given plane is

2x-y+z = 5

dividing both sides by 5 we get,

=> 2x/5 + (-y/5) + z/5 = 5/5

=> x/(5/2) + y/(-5) + z/5 = 1..................(.eq.1)

we know that ,the equation of the plane is,

x/a + y/b + z/c = 1............(eq.2)

comparing 1 and 2 ,we get .

a = 5/2

a = 5/2 b = -5

a = 5/2 b = -5c = 5