Question

Reduce the equation to normal form: x-√3 y +8 =0
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Answer 1

Answer:

y=MX+c

x-√3y +8 =0

-√3y = -8-x

-√3y = -(8+X)

y = 8/√3 + X/√3

compare with y=MX+c

m= 1/√3

m= tan theta

1/√3= tan theta

tan π/6 = tan theta

theta = π/6

Normal form

cos¶ + sin¶ = p