reduction CHCl₃+KOH reduction
[A] ⟶ [B] ⟶ [C] ⟶ N-Methylanil ine
,A is
(a) Formaldehyde (b) Trichloromethane
(c) Nitrobenzene (d) Toluene
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Answer:
it will forms trichloromethane ok thnx✌☺
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(c) Nitrobenzene
Explanation:
Since N-methyl aniline is a 2∘ amine C must be an isocyanide which implies that B is 1∘ aromic amine and hence A is nitrobenzene. Please refer to the attached picture for a diagrammatic representation of the above information.
Option C is the answer.
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