Chemistry, asked by deepuseth1319, 10 months ago

reduction CHCl₃+KOH reduction
[A] ⟶ [B] ⟶ [C] ⟶ N-Methylanil ine
,A is

(a) Formaldehyde (b) Trichloromethane
(c) Nitrobenzene (d) Toluene

Answers

Answered by Anonymous
3

Answer:

it will forms trichloromethane ok thnx✌☺

Answered by topwriters
0

(c) Nitrobenzene

Explanation:

Since N-methyl aniline is a 2∘ amine C must be an isocyanide which implies that B is 1∘ aromic amine and hence A is nitrobenzene. Please refer to the attached picture for a diagrammatic representation of the above information.

Option C is the answer.

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