Question

Reduction formula for the integral cos^nxdx
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Answer 1

Step-by-step explanation:

To derive the reduction formula, rewrite cosnx as cosxcosn−1x and then integrate by parts. But this gives you (n−1)∫cosnxdx somewhere on the right: ... n∫cosnxdx=sinxcosn−1x+(n−1)∫cosn−2xdx

Answer 2

Answer:

To derive the reduction formula, rewrite cosnx as cosxcosn−1x and then integrate by parts. But this gives you (n−1)∫cosnxdx somewhere on the right: n∫cosnxdx=sinxcosn−1x+(n−1)∫cosn−2xdx .

Explanation:

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