Question

Reduction method x-y+z=1 , 2x-y=1, 3x+3y-4z=2

Answer 1

x-y+z=1. ....………(1)
2x-y=1. …………(2)
3x+3y-4z=2. …………(3)

(1)-(2)

x-y+z-2x+y=1-1
-x-y=0
x+y=0. …………(4)

(2)-(4)
2x-y-x+y=1
x=1

putting value of x in equation 2 we get
2-y=1
-y=-1
y=1

putting values of x and y in equation 1 we get
1-1+z=1
z=1