Question

reduction of 20% in the price enables to buy 2.5 kg more for Rs. 100. What is the reduced price​

Answer 1

Answer:

Let the price per kg of sugar be x.

So for Rs.160 .160/x kg can be bought.

Now price has reduced by 20% ie for 160/x qty one has to pay only 4/5 of 160 or Rs.128.

With the difference in price of Rs 32/- (2.5 kg) or 5/2 kg of sugar can be got.

So with the new price: For Rs.128 ….128 × 5/2 ÷32 or 10 kgs of sugar can be bought or totally for Rs.160/- 10+2.5 or 12.5 kgs of sugar could be bought.

So originally 10 kgs of sugar could be bought for Rs.160/-

If the price is reduced by 20% and the money you save on that reduction allows you to buy 2,5kg more rice this means the following:

Total money spent remains the same =160

2,5kg at the new price costs 20% of 160

Or 2,5kg rice at the new price =32

2,5 can be written as 5/2

So

5/2 . new price=32

5. New price = 64

New price = 64/5= 12,8

New price = 80% of old price= 4/5 . Old price

5/4 .new price = old price

5/4. 12,8= 16

Original price was 16

Productivity maximized.

20% = 2.5

100% = 12.5

Orinal suger = 12.5- 2.5= 10kg

Original price = 160/10 =Rs 16 per kg

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A reduction of 20% in the price of rice enables a person to buy 3.5 kg more for Rs. 77. What is the original price per kg?

A reduction of 20% in the price of sugar will enable customers to buy 2 kg more for rupees 100. What is the the original price and reduced price?

A reduction of 20% in the price of apples enables a buyer to get one dozen more for Rs 50.Find the reduced price per dozen of apples?

Let price per kg be p and weight we can buy on new price be x.

so new price = p - 20%p = 0.8p.

so 0.8p * x = 160

p * x = 200 …(a)

now earlier for old price per kg i.e. p we get 2.5 kg less for same cost 160 so

p * (x-2.5) = 160

x = (160+2.5p)/p

put this in (a) equation

p * (160+2.5p)/p = 200

p = (200–160)/2.5 = 16

so our answer is 16

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For 2.5 kg 160 Rs

For 1 kg. 64 [20% reduction]

Original price 64*100/80

Original price = 80 Rs.

If u cross check 80*20% =16

80-16 =64 [20%reduction price]

(20/100) *160=32 rs, this is given for extra 2.5 kg

So for 1 kg he paid 12.8 rs

So actual price is x*80/100=12.8( here 20% reduction so take 100–20= 80)

Ans is x=16

R = Rate, M = Mass

R x M =160

.8 R x (M + 2.5) = 160

R x M = .8 R x (M + 2.5)

Divide both sides by R, distribute the right side, and bring like terms together.

.2 M = 2

M=10

Therefore R=16.