Question

Reduction of boron trichloride by hydrogen reaction

Answer 1

Answer:

2BCl3 + 3H2 → 6HCl + 2B

or BCl3 + 3/2H2 → 3HCl + B

10.8 g boron requires hydrogen = 3/2 22.4 L

21.6 g boron will require hydrogen

= 3x22.4/(2x10.8) = 67.2 L