Science, asked by varunmachhirke561, 1 day ago

• Reduction of ketone by NaBH4 or
LiAlH4 as a catalyst gives
Answer
A. Primary alcohol
B. Secondary Alcohol
C. Tertiary alcohol
D. None of these​

Answers

Answered by subhendu20
0

Answer:

Explanation:

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Answered by sarahssynergy
0

Reduction of ketones by Sodium Borohydride or Lithium aluminumhydride gives:

B. Secondary alcohol

Explanation:

Reduction of ketones by Sodium Borohydride or Lithium aluminumhydride gives: Secondary alcohol.

  • Reduction of  Ketones produces secondary alcohols.
  • Lithium Aluminumhydride and Sodium Borohydrides are reducing agents and act on the compound to reduce it.
  • Lithium Alminumhydride is a much stronger reducing agent when compared to Sodium borohydride but both these agents reduce ketones to Secondary alcohols.
  • Aldehydes and Ketones readily  react with hydrides to be reduced. Aldehydes on reduction produce primary alcohols and Ketones reduce into secondary alcohols.
  • An acid-base reaction, acidic workup takes place to convert the intermediate metal alkoxides  into alcohols.
  • Secondary alcohols are have the hydroxyl group on the second Carbon atom, bonded by two other carbon atoms.

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