Chemistry, asked by Las9abirdpoonanmath, 1 year ago

reduction of metal oxide is easier if the metal in liquid state?

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Answered by Vishwampatidar
4
In the liquid, the temperature of the substance is higher. As per the Ellingham diagram, the value of ∆G for the formation of metal oxide increases as temperature increases.. At the higher temperatures, the reduction of metal oxide is easier. For the reduction of metal oxide, the Gibbs energy should be negative. In solid state, the entropy or randomness will be less due to high intramolecular force of attraction while in liquid state, the entropy will be more comparatively, Therefore Gibbs energy will be more negative.
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