Question

Reduction potential of hydrogen electrode at 1 atm pressure of H2 gas dipped in 0.01 M HCl solution at 298 K is
a) -0.872 V
b) +0.325 V
c) -0.118 V
d) +0.059 V

Answer 1

Answer:

4th option is the ans

Explanation:

Answer 2

The standard potential is taken to be zero and the further given information in the question is;

The pressure of Hydrogen gas = 1 atm

The concentration of H⁺ = 0.01 M

Temperature = 298K

2H⁺ + 2 e⁻ → H₂ (g)

Using the Nernst Equation,

$E_{cell} = E^{o} _{cell} - \frac{0.0591}{n} log [\frac{P_{H2} }{(H^{+})^{2} } ]$

$E_{cell} = 0 - \frac{0.0591}{2} log [\frac{1}{(0.01)^{2} } ]$

$E_{cell} = + 0.059 V$

The correct answer for this question is option D.