Question

Reema being a plant oliver decides to open a nursery and she bought five plants
with pots. She wants to place pots in such a way that number of pots in first
row is 3, in the second row is 5 and in the third row is 7 and So on.
.
(i) If Reema wants to place 120 pots in total then the total number of rows
formed in this arrangement is.....
a) 12
b) 10
c) 8
d) 14
Find the difference in number of pots placed in the 8row and 3 row?
a) 10
b) 11 c) 14 d) 15
(iii) If for an AP, an=4n+ 5. find the common difference?
a) 5
b) 4
c) 1
d) 0​

Answer 1

Hey,

d = 5 - 3 = 2

a = 3

(i) Option B = 120

So the AP would be : 3 , 5 , 7 , 9 , 11 , 13 , 15 , 17 , 19 , 21 ....

By adding the following 10 terms the sum would be 120

(ii)Option A = 10

The  number of pots in 8th row is 17 and the number of pots in 3rd row is 7

Therefore : 17 - 7 = 10

(iii)Option C = 1

Please mark this answer as brainliest!!!