Math, asked by akashojha9103, 1 year ago

Reema can complete a piece of work in 12 days while Seema can the same work in 18 days. If they both work together, then how many days will be required to finish the work?

Answers

Answered by spiderman2019
6

Answer:

36/5 days.

Step-by-step explanation:

In one day, reema can do = 1/12 part.

In one day, Seema can do = 1/18 part

In one day, reema and Seema together do = 1/12 + 1/18 =  3 + 2 / 36 = 5/36 part.

So both of them will together do the work in 36/5 days.

Answered by H2010
0

Answer:

36/5 days.

Step-by-step explanation:

In one day, reema can do = 1/12 part.

In one day, Seema can do = 1/18 part.

In one day, reema and Seema together do = 1/12 + 1/18 =  3 + 2 / 36 = 5/36 part.

So both of them will together do the work in 36/5 days.

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