Math, asked by fussion7384, 9 months ago

Reema is twice as old as varun .five yrs ago , her age was three times varun's age . Find her present age .

Answers

Answered by darshil7984695838
2

Answer:

it's easy

Step-by-step explanation:

(1)reema is twise as old varun(reema=x)

(Varun=y)

2x=y

(2) after 5 year ago reema is three times

of varuns age then ,

1st 2 times× 2nd 3times

2x+5=y. (x=3)

2(3)+5=y

6+5=y

11=y. varun has

then reema has 11×6 =66 think because reema and Varun age is between twise

on the time wasn't stop for this question

because u say after 5 year reema age is three times of varuns age I think the question is wrong (I think only)

Answered by Sauron
5

Answer:

Reema is 20 years old and Varun is 10 years.

Step-by-step explanation:

Given :

Reema is = twice old as Varun

Fave years ago, Reema was 5 times Varun's age

To find :

Their present ages

Solution :

Let their present ages be -

  • Varun as y
  • Reema as 2y

Ages 5 years ago -

  • Varun = y - 5
  • Reema = 2y - 5

★ 2y - 5 = 3(y - 5)

⇒ 2y - 5 = 3y - 15

⇒ 2y - 3y = - 15 + 5

⇒ –y = –10

⇒ y = 10

Varun's present age = 10 years

\rule{300}{1.5}

Reema's present age -

⇒ 2(10)

⇒ 20

Reema's present age = 20 years

Therefore, Reema is 20 years old and Varun is 10 years.

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