Question

reema's age is 6 years less than twice of deepti's age.If reema is 42 years old, find deepti's age​

Answer 1

Answer:

deepti is 18 years old

Step-by-step explanation:

let deepti's age be X

so reema's will be

2x-6=42.

2x=42-6

2x=36

x=36/2

x=18

now deepti's age=18 years

and reema's age= 42 years

Answer 2

Answer:

24 years old

Step-by-step explanation:

Reema's age = 6 years lesser than twice of Deepti 's age .

Now consider Deepti's age as X and 6 years more than Reema's age as Y.

Deepti's age =

$x \times 2 - 6 \\ y - 6$

Now if Reema's age is 6 years lesser than twice of Deepti's age,then we have to add Reema's age(42)with 6.

$42 + 6 = 48$

Finally, you have to divide 48 by 2.

$48 \div 2 = 24$

Therefore,Deepti's age is 24.

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