Math, asked by am0816267, 10 months ago

Reema's Mother is four times as old as Reema. After 5 years, her mother will be 3 times as old as she will be then. Find their present ages. Please Tell the Answer

Answers

Answered by Anonymous
16

Let age of Reema be x and mother be y.

Acc. to question,

4x = y......(i)

and y+5 = 3(x+5)

⇒ y+5 = 3x + 15

⇒ y-3x = 10

⇒ 4x-3x = 10 (∵4x is equal to y)

⇒ x = 10

∴ y = 4x

= 4×10

= 40

Therefore, present age of Reema is 10 years and mother is 40 years.

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Answered by Anonymous
118

\Large{\underline{\underline{\mathrm{\purple{Given}}}}}

Reema's Mother is four times as old as Reema. After 5 years, her mother will be 3 times as old as she will be then.

\Large{\underline{\underline{\mathrm{\purple{Find\;out}}}}}

Present age of Remma and her mother

\Large{\underline{\underline{\mathrm{\purple{Solution}}}}}

Let the Remma present age be x and her mother present age be 4x

*According to the given condition*

  • After 5 years
  • Remma's age = (x + 5)
  • Remma's mother age = (4x + 5)

\implies\sf 4x + 5 = 3(x + 5) \\ \\ \\ \implies\sf  4x + 5 = 3x + 15 \\ \\ \\ \implies\sf 4x - 3x = 15 - 5 \\ \\ \\ \implies\sf   x = 10

{\underline{\boxed{\tt{\red{Present\:age\:of\:Remma=x=10years}}}}}

{\underline{\boxed{\tt{\red{Present\:age\:of\:Remma's\:mother=4x=40years}}}}}


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