Reema's mother is now three times as old as reema's present age. After 2years her mother will be 10years more than twice reema's present age. Find their ages
Answers
Answered by
73
Here is your answer dear⬇️⬇️
Let Reema's age be x
Let her mother's age be 3x
After two years
Reema's age = x + 2
Reema's mother age = 3x + 2
3x + 2 = 2(x + 2) + 10
3x + 2 = 2x + 10
3x = 2x + 10 - 2
3x = 2x + 8
3x - 2x = 8
x = 8
Reema's age = 8
Her mom's age = 3x = 3 × x = 3 × 8 = 24
Let Reema's age be x
Let her mother's age be 3x
After two years
Reema's age = x + 2
Reema's mother age = 3x + 2
3x + 2 = 2(x + 2) + 10
3x + 2 = 2x + 10
3x = 2x + 10 - 2
3x = 2x + 8
3x - 2x = 8
x = 8
Reema's age = 8
Her mom's age = 3x = 3 × x = 3 × 8 = 24
BrainlyPrincess:
thanks for correcting roshankumarpirpcshx
Answered by
63
Hey!!
Let's take Reema's age as ' x '
Mother's age will be = 3x
After two years:
Reema = x + 2
Mother = 3x + 2
Equation :
2 ( x ) + 10 = 3x + 2
2x + 10 = 3x + 2
8 = x
Reema present age = 8 years
Mother present = 24 years
Hope my answer helps!
#BeBrainly
@sid071
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