Chemistry, asked by shivanisanjaigk74, 3 days ago

Reema took 5ml of Lead Nitrate solution in a beaker and added approximately 4ml of  Potassium Iodide solution to it. What would she observe braniy​

Answers

Answered by cedrekwatingmailcom
6

Answer:

the reaction, Pb(NO3)2 represents lead nitrate, KI represents potassium iodide, KNO3 represents potassium nitrate and PbI2 represents lead iodide. PbI2 is a precipitate yellow in colour thus making mentioned reaction a precipitation reaction as well

Explanation:

the reaction, Pb(NO3)2 represents lead nitrate, KI represents potassium iodide, KNO3 represents potassium nitrate and PbI2 represents lead iodide. PbI2 is a precipitate yellow in colour thus making mentioned reaction a precipitation reaction as well

Answered by rahul123437
1

When 5mL of lead nitrate solution is mixed with 4mL of Potassium Iodide solution then, a yellow precipitate of Lead Iodide is formed and get deposited at the bottom of the beaker leaving behind Potassium nitrate in the solution.

PRECIPITATION REACTION

  • A type of reaction that involves the formation of an insoluble salt when two solutions of soluble salts are combined and made to react with each other.
  • The insoluble salt is settled at the bottom and is known as a precipitate.
  • The reaction involves the formation of cation and anion pairs in the resulting insoluble salt.
  • When lead nitrate is mixed with potassium iodide, the reaction involved is -                Pb((NO_{3} )_{2} + KI ⇒   KNO_{3}  + PbI_2
  • The yellow precipitate of lead iodide is formed by the double displacement reaction.

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