Question

Reema took a wire of length 44 cm and bent it into the shape of a circle. Find the radius of that circle.If the same wire is bent into the shape of a square .what will be the length of each of its sides? (use π=22/7) PLZ PLZ

Answer 1

Answer :

• The radius of the circle = 7 cm
• The length of the side of the square = 11 cm

Step-by-step explanation :

Given,

• The length of the wire, l = 44 cm

To find,

• The radius of the circle when the wire is bent it into the shape of a circle
• The side of the square when the same wire is bent into the shape of a square

Solution,

[1] The wire is bent into the shape of the circle,

Let 'r' be the radius of the circle

   $\setlength{\unitlength}{0.57cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large r cm}\end{picture}$

➔ The length of the wire will be equal to the circumference of the circle.

 ➙    l = 2πr

 ➙  44 cm = 2(22/7) × r

 ➙   44 = 44/7 × r

 ➙    r = 7 cm

The radius of the circle = 7 cm

[2]  The wire is bent into the shape of the square,

Let 'a' be the length of the side of the square

$\setlength{\unitlength}{0.5 cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(4,0){2}{\line(0,1){4}}\multiput(0,0)(0,4){2}{\line(1,0){4}}\put(1.5,-0.6){\bf\large a\ cm}\put(4.4,2){\bf\large a\ cm}\end{picture}$

➔ The length of the wire is equal to the perimeter of the square.

   ➙    l = 4a

   ➙   44 cm = 4a

   ➙   a = 44/4

   ➙   a = 11 cm

The length of the side of the square = 11 cm