Math, asked by manasmuraliraj69, 1 year ago

Reemas mother is four times as old as reema . after 5 years her mother will be three times as old as a he will be then . find their present ages

Answers

Answered by debtwenty12pe7hvl
1

Reema's age be = x

So mothers age be = 4x

AFTER 5 YEARS

Reema's age = x+5

Mother's age = 4x+5

ATQ(According To Question)

4x+5 = 3(x+5)

4x+5 = 3x+15

4x-3x = 15-5

x = 10

So their present ages=

Reema's age= 10 years

Mother's age= 4x

= 4*10

= 40 years  ans

Answered by riya5395
0

Answer:

let the reema age is x

then

her mother is for 4x

after 5 years

Reema were X + 5

her mother 4 x + 5

according to the question,

her mother will be three times

(X + 5)3 =4 x + 5

3 X + 15 = 4 x + 5

3 x -4 x = 5 - 15

- x= - 10

- and - cancel,then

X=10

reema age is 20

her mother age is 40

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