Question

Reemu read (1/5)th pages of a book. If she reads further 40 pages, she would have read (7/10)th pages of the book. How many pages are left to be read?​

Answer 1

$\red{\bigstar \large\underline{\boxed{\bf\pink{Answer:-}}}}$

Let the total number of pages = x

$\sf \red{ = \frac{x}{5} + 40 = \frac{7x}{10} }$

$\sf \purple{ = 7x - \frac{2x}{10} = 40}$

$\sf \green{ = \frac{5x}{10} = 40 }$

$\sf \orange{ = \frac{x}{2} = 40}$

${ \boxed {\sf \pink{ \mapsto \: x = 80}}}$

Remaining pages =

$\sf \color{yellow} = x - \frac{7x}{10}$

$\sf \color{violet} \frac{3x}{10}$

$\sf \color{skyblue} \frac{3}{ \cancel10} \times \cancel 80$

${ \boxed{ \sf \pink{ \mapsto \: 24 \: pages}}}$

$\sf \gray{ \therefore \: the \: number \: of \: pages \: left = 24 }$

Hope it helps

Answer 2

$\huge \colorbox{pink}{AɳSɯEɾ}$

From the question it is given that,

$\bold \orange{Reemu \: read \: (1/5) th  \: pages \: of \: a \: book. }$

Let us assume the total number of pages in the book be ‘P’.

Then, number of pages read by Reemu = (1/5) of P

= (1/5) × P

And also it is given the question,

If she reads further 40 pages, she would have read (7/10)th pages of the book. = (7/10) × P

So, ((1/5) × P) + 40 = (7/10) × P (P + 200)/5 = (7P/10)

By cross mutliplication we get,

2P + 400 = 7P 5P = 400 P = 400/5 …

P = 80

$\fbox \pink{Then, \: pages \: read \: by \: Reema = Total pages – Pages read}$

P – (7P/10) = (3P/10) (3/10) × 80 24 pages

$\mathfrak \red{Therefore, \: 24 \: pages \: are \: left \: to \: be \: read.}</p><p>$

Hope it helps you!❤