reemu read 1/5th pages of she reads further 40 pages she would have read 7/10 th page of the book. how many pages are left to be read
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Answer:
From the question it is given that,
Reemu read (1/5)th pages of a book.
Let us assume the total number of pages in the book be ‘P’.
Then, number of pages read by Reemu = (1/5) of P
= (1/5) × P
And also it is given the question,
If she reads further 40 pages, she would have read (7/10)th pages of the book.
= (7/10)× P
So,
((1/5) × P) + 40 = (7/10) × P
(P + 200)/5 = (7P/10)
By cross mutliplication we get,
2P + 400 = 7P
5P= 400
P = 400/5 … [divide both numerator and denominator by 5]
P = 80
Then, pages read by Reema = Total pages – Pages read
P – (7P/10) = (3P/10)
(3/10) × 80 24 pages
Therefore, 24 pages are left to be read.