Question

Reemu reads 1/5th pages of a book. If she reads further 40 pages, she would have read 7/10thpage of the book. How many pages are left to be read? * a 70 b 60 b 80​

Answer 1

ANSWER:

GIVEN

Reemu reads 1/5 th of pages of a book

SOLUTION

Let us assume the total number of pages in the book be ‘P’.

Then, number of pages read by Reemu = (1/5) of P = (1/5) × P

And also it is given the question, If she reads further 40 pages, she would have read (7/10)th pages of the book. then,(7/10) × P

So, ((1/5) × P) + 40 = (7/10) × P (P + 200)/5 = (7P/10)

By cross mutliplication we get,

2P + 400 = 7P 5P = 400 P = 400/5 … [divide both numerator and denominator by 5]

P = 80

Then, pages read by Reema = Total pages – Pages read P – (7P/10) = (3P/10) (3/10) × 80 24 pages .

Therefore, 24 pages are left to be read.

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Answer 2

Solution :-

Let us assume that, total pages in the books are x .

so,

→ Reemu reads = (1/5)th pages of x = (x/5) pages .

now,

→ She reads further = 40 pages .

then,

→ she would have read = (7/10)th pages .

A/q,

→ (x/5) + 40 = (7x/10)

→ (7x/10) - (x/5) = 40

→ (7x - 2x)10 = 40

→ (5x/10) = 40

→ (x/2) = 40

→ x = 80 pages .

therefore , the book has total 80 pages .

hence,

→ Pages Left to be read = 80 - (7/10) of 80 = 80[1 - (7/10)] = 80 * (3/10) = 24 pages (Ans.)

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