Question

Reemu reads 1/5th pages of a book. If she reads further 40 pages, she would have read 7/10thpage of the book. How many pages are left to be read? * a 70 b 60 b 80​

Answer 1

Answer:

From the question it is given that, Reemu read (1/5)th pages of a book. Let us assume the total number of pages in the book be ‘P’. Then, number of pages read by Reemu = (1/5) of P = (1/5) × P And also it is given the question, If she reads further 40 pages, she would have read (7/10)th pages of the book. = (7/10) × P So, ((1/5) × P) + 40 = (7/10) × P (P + 200)/5 = (7P/10) By cross mutliplication we get, 2P + 400 = 7P 5P = 400 P = 400/5 … [divide both numerator and denominator by 5] P = 80 Then, pages read by Reema = Total pages – Pages read P – (7P/10) = (3P/10) (3/10) × 80 24 pages Therefore, 24 pages are left to be readRead more on Sarthaks.com - https://www.sarthaks.com/787229/reemu-read-the pages-of-book-if-she-reads-further-pages-she-would-have-read-the

pages-the-book.