Reena and Ruchira borrowed rupees 60000and50000 respectively for a period of 3 years . Reena paid simple interest at the rate of 10%p.a., while Ruchira paid compound interest at the rate of 10%p.a. compounded anually. Who paid more interest and by how much ?
Answers
Principal amount for Reena P = $60000
Rate of interest R =10%
Time T = 3 years
Simple interest I = P×R×T
I = 60000×0.10×3 = $ 18000
Principal for Ruchira P = $50000
Rate of interest I = 10%
Time T = 3 years
Compound interest = P[1+R]ⁿ
=
=
= $66550
Hence Ruchira pays more interest than Reena by $66550-$18000 = $48550
Reena and Ruchira borrowed 60000 and 50000 for a period of three years. Reena payed back this amount at the 10 % simple interest while Ruchira payed back this amount at 10 % compounded annually.
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Who paid more interest and by how much ?
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~ Formula Used :
~ Calculating the Interest paid by Reena :
Here :
➳ P = 60000
➳ R = 10 %
➳ T = 3 years
Calculating Starts :
~ Calculating the Interest paid by Ruchira :
Here :
➳ P = 50000
➳ R = 10 %
➳ T = 3 years
Calculating Starts :
~ Calculating the Difference :
Therefore :
❝ Reena paid more interest and by ₹ 1450 . ❞
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