Reena borrowed from Kamal certain sum for 2 years at S.I . Reena Lent this sum to hamid at the same rate for 2 years . Hse recieved 110 as C.I . But paid 100 as S.I . Find the sum and R%.
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CI-SI=10Rs.
SI for 2years=SI1 + SI 2= 2*SI {since,SI is same each yr]
CI for 2 years= SI1 + SI2 + R/100* SI1= SI + SI + (R/100)* SI
CI-SI = 2*SI + R/100*SI - 2*SI
(SI after 2 years=100, hence SI per year=50Rs)
10=R*50/100....R=20%
P=SI*100/R*T = 50*100/20*1 = 250Rs.
SI for 2years=SI1 + SI 2= 2*SI {since,SI is same each yr]
CI for 2 years= SI1 + SI2 + R/100* SI1= SI + SI + (R/100)* SI
CI-SI = 2*SI + R/100*SI - 2*SI
(SI after 2 years=100, hence SI per year=50Rs)
10=R*50/100....R=20%
P=SI*100/R*T = 50*100/20*1 = 250Rs.
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