Question

Reena has pens and pencils which together are 40 in number. If she has 5 more pencils and 5 less pens, the number of pencils would become 4 times the number of pens. Find the original number of pens and pencils.

Answer 1

Given : Reena has pens and pencils which together are 40 in number. If she has 5 more pencils and 5 less pens, the number of pencils would become 4 times the number of pens.  

 

Solution:

Let the number of pens be x and that of pencil be y, then,

x + y = 40         ……...…(1)

and (y + 5) = 4(x - 5)

y + 5 = 4x - 20

5 + 20 = 4x - y

4x - y = 25   ………..…(2)

On Adding equation (1) and equation(2), we get :  

x + y = 40  

4x - y = 25

----------------

5x = 65

x = 65/5

x = 13

On Putting x = 13 in equation (1), we get :

x + y = 40

13 + y = 40

y = 40 - 13  

y =  27

Hence, the original number of pens are 13 and pencils are 27.

Hope this answer will help you…

 

Some more questions from this chapter :  

5 pens and 6 pencils together cost Rs 9 and 3 pens and 2 pencils cost Rs 5. Find the cost of 1 pen and 1 pencil.

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7 audio cassettes and 3 video cassettes cost Rs 1110, while 5 audio cassettes and 4 video cassettes cost Rs 1350. Find the cost of an audio cassette and a video cassette.

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Answer 2

Answer:

Step-by-step explanation:

Solution:-

Let the number of pens be x.

And the number of pencils be y.

According to the Question,

1st Part

⇒ x + y = 40 .....(i)

2nd Part

y + 5 = 4(x – 5)

⇒ y = 4x - 25 ....(ii)

Solving Eq (i) and Eq (ii), we get

⇒ x + y - y = 40 - 4x + 25

⇒ 5x = 65

⇒ x = 13

Putting x's value in equation (i),we get

⇒ 13 + y = 40

⇒ y = 27

Hence, Reena has 13 pens and 27 pencils.