Math, asked by rneeraj139, 10 days ago

# reena has pens and pencils which together are 40 in number if she has 5 more pencils and 5 less pens then number of pencil would become 4 times the number of pens find the original number of pens and pencils

4

Assumption:

Number of pens be p

Also,

Pencil be t

So,

p + t = 40 ……...…(1)

Also,

(t + 5) = 4(p - 5)

t + 5 = 4p - 20

5 + 20 = 4p - t

4p - t = 25 ………..…(2)

5p = 65

p = 65/5

p = 13

Substituting value of p in (1),

p + t = 40

13 + t = 40

t = 40 - 13

t = 27

Therefore,

Original number of pens = 13

Original number of pencils = 27

31

Let the number of pens be x and that of pencil be y. Then,

x + y = 40 .......…..…(1)

and (y + 5) = 4 (x - 5)

➠ y + 5 = 4x - 20

➠ 5 + 20 = 4x - y

➠ 4x - y = 25 .............(2)

Adding equation (1) and equation (2), We Get:

x + 4x = 40 + 25

➠ 5x = 65

➠ x = 65/5

x = 13

Putting x = 13 in equation (1), We Get:

13 + y = 40

➠ y = 40 - 13 - 27

• Hence, Reema has 13 Pens and 27 Pencils.

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