Math, asked by wafeeqasheikh, 20 days ago

Reena is 3 times as old as her daughter. In 5 years, the sum of their ages will be 62 years. Find the daughter’s present age.​

Answers

Answered by crazybot007
26

Answer:-

Let

Daughter's age be x

Reena's age =3x(5 years after)

Daughter's age be x-5

Reena's age be 3x-5

Sum of age at this time=(x - 5)+(3x - 5)=62

⇒4x+(-10)=62

⇒4x=62+10[bringing (- 10) to this side]

⇒x=72/4=18

⇒(3x - 5)=3×18 - 5

⇒54 - 5 =49↦Reena's age

⇒18 - 5 = 13↦daughter's age

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Answered by Sauron
35

Step-by-step explanation:

Solution :

Let,

  • Present age of Reena's daughter = x

  • Present age of Reena = 3x

In 5 years,

  • Age of Reena's daughter = x + 5

  • Age of Reena = 3x + 5

According to the Question :

The sum of their ages will be 62 years

⇒ (x + 5) + (3x + 5) = 62

⇒ 4x + 10 = 62

⇒ 4x = 62 - 10

⇒ 4x = 52

⇒ x = 52/4

x = 13

Present age of Reena's daughter = 13 year

Therefore, the daughter’s present age is 13 year

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