Question

Reena is 6 year older than her brother Ajay . If the sum of their ages is 28 years,whatever are their present ages?

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Answer 1

Answer:

So, the age of Reena is x+6 years. According to the problem, we are given that the sum of ages of Reena and Ajay is 28 years. So, we get x+x+6=28. ⇒2x=22

Step-by-step explanation:

Answer 2

Required Solution :

★ Present age of Reena = 17 years ★

★ Present age of Ajay = 11 years ★

Given:

• Age of Reena = 6 year older than her brother Ajay.

• Sum of their ages is 28 years.

To calculate:

• Their present ages.

Calculation:

Let the present age of Ajay be x years.

Then, age of Reena becomes ( 6 + x ) years.

Now, according to the question:

→ Age of Reena + Age of Ajay = 28 years

Substituting the values :

→ ( 6 + x ) + x = 28

→ 6 + x + x = 28

→ 6 + 2x = 28

→ 2x = 28 - 6

→ 2x = 22

→ x = $\sf {\dfrac{22}{2}}$

→ x = 11 years

Therefore,

• Age of Ajay ( x years ) = 11 years

• Age of Reena ( 6 + x years )

→ Age of Reena = ( 6 + 11 ) years

→ Age of Reena = 17 years

Verification:

As the question states that sum of their ages is 28. So, let us insert the value in the suitable equation to justify our answer.

→ Age of Reena + Age of Ajay = 28 years

→ ( 17 + 11 )years = 28 years

→ 28 years = 28 years

LHS = RHS, hence verified!