Question

Reena is 6 years older than her brother Ajay.if sum of their ages is 28 year.what are their present age

Answer 1

Let the age of Ajay be x.

Then the age of Reena will be x+6.

Hence Sum of their age will be (x)+(x+6).

x+x+6=28

2x+6=28

2x=22

x=22/2

x=11

Hence their present age of Reena is 17.

Present age of Ajay is 11.

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Answer 2

let reenas age be x

let her brothers age be y

sum if their age

x+y = 28....(1)

reena is x=y+6...(2)

substitute 2 in 1

y+6+y=28

2y+6=28

2y=28-6

2y=22

y=11

substitute y=11 in 2

x=11+6

x=17