Reena is 6 years older than her brother ajay.if the sum of their ages is 28 years,what are their present ages
Answers
Answered by
67
Let ajay's age be x, then Reena's age will be x+6.
Now ATQ, x+(x+6)=28
So, 2x+6=28
2x=22
x=11
Therefore Ajay's age is 11 years and that of Reena will be 17 (11+6) years.
Now ATQ, x+(x+6)=28
So, 2x+6=28
2x=22
x=11
Therefore Ajay's age is 11 years and that of Reena will be 17 (11+6) years.
Answered by
53
let ajay's age be 'x'
then reena's age will be 'x+6'
.: ATP:-
x+(x+6)=28
=>x+x+6=28
=>2x+6=28
=>2x=28-6=22
=>[x=22÷2=11]
.: ajay's age= x= 11
reena's age= (x+6)= (11+6)= 17
then reena's age will be 'x+6'
.: ATP:-
x+(x+6)=28
=>x+x+6=28
=>2x+6=28
=>2x=28-6=22
=>[x=22÷2=11]
.: ajay's age= x= 11
reena's age= (x+6)= (11+6)= 17
Similar questions