Math, asked by samznair4167, 1 year ago

Reena is 6 years older than her brother ajay.if the sum of their ages is 28 years,what are their present ages

Answers

Answered by Neerav34
67
Let ajay's age be x, then Reena's age will be x+6.
Now ATQ, x+(x+6)=28
So, 2x+6=28
2x=22
x=11
Therefore Ajay's age is 11 years and that of Reena will be 17 (11+6) years.
Answered by anurag338
53
let ajay's age be 'x'
then reena's age will be 'x+6'
.: ATP:-
x+(x+6)=28
=>x+x+6=28
=>2x+6=28
=>2x=28-6=22
=>[x=22÷2=11]
.: ajay's age= x= 11
reena's age= (x+6)= (11+6)= 17
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