Question

Reena is 6 years older than her brother Ajay . If the sum of their ages is 28 years , what are their present ages

Answer 1

let ajay's age be x years
Reena is 6 years older than Ajay so, Reena's age =x+6 years

s of their ages is 28
so, x+x+6=28
2x+6=28
2x=28-6
2x=22
x=22/2
x=11
so, ajay's age us 11 years
and Reena's age is x+6
=11+6
17 years

Answer 2

Hii here is your answer.......

let the age of Reena be x

& ----------------brother be y

According to question

x=6+y--------(1)

◆sum of their ages is 28

so,
x+y=28------(2)
.
put value of x in equation(2)

◆6+y+y=28
◆2y=28-6
◆2y=22
◆y=11


Now put value of y in equation in equation (2)

◆x+11=28
◆x=28-11
◆x=17

So the present age of Reena is 17
And present age of her brother is 11