Question

Reena is 6 years older than her brother Ajay. If the sum of their ages is 28 years . What are their present ages?​

Answer 1

Step-by-step explanation:

let the age of Ajay be $x$.

As the age of Reena is 6 more than Ajay's age, let the age of Rena be $6+x$.

Now, As the question states that sum of their ages is 28,

$x + 6 + x = 28 \\ 2x + 6 = 28 \\ 2x = 28 - 6 \\ 2x = 22 \\ x = \frac{22}{2} \\ x = 11$

therefore, Age of Ajay = $x$ = 11

Age of Reena = $x + 6$ = $6+11$ = 17