Math, asked by Praveenchezhian9889, 1 year ago

Reena is 6year older than her brother ajay. If the sum of their ages is 28 years,find their present ages?

Answers

Answered by jmodi005
2

x+x+6 = 28

2x=. 28-6

2x=12

x= 6



Reena is 12 as x+6 = 6+6

And brother 6 years


Hope it works out for you





Mark brainliest


Answered by sejalchoudhary54
4

Let the age of Ajay be x years.

So the age of Reena=x+6


According to question,

x+x+6=28

2x+6=28

2x=22

x=11


Therefore,the age of Ajay is

x=11

and the age of Reena is

x+6=11+6=17


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