Math, asked by 7780608913, 1 year ago

Reena is twice as old as suma
Three years ago she was three times as old as suma.how old in Reena now?

Answers

Answered by sonuvuce
12

Answer:

Reena is 12 years old

Step-by-step explanation:

Let the present age of Suma = x years

Then the present age of Reena = 2x years

Three years ago, age of Suma = x - 3

Three years ago, age of Reena = 2x - 3

According to the question

2x-3=3(x-3)

\implies 2x-3=3x-9

\implies 3x-2x=9-3

\implies x=6

Therefore the present age of Suma = 6 years

Present age of Reena  = 12 years

Therefore, Reena is 12 years old

Hope this helps.

Answered by SerenaBochenek
1

Given:

Reena is 2 times older than Suma even though she was 3 times older than Suma 3 years ago.

To Find:

Reena's present age = ?

Solution:

Let,

Suma's present age be "x".

Then,

Reena's present age be "2x".

3 years ago,

Suma's age = x-3

Reena's age = 2x-3

According to the question,

⇒  2x-3=3(x-3)

⇒  2x-3=3x-9

⇒  3x-2x=9-3

⇒  x=6

Therefore,

Suma's present age = 6 years

Reena's present age = 2x

                                   = 2\times 6

                                   = 12 \ years

So that Reena is 12 years old.

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