Question

Reena is twice as old as sunitha. Three years ago, she was three times as old as sunitha. How old is reena now?

Answer 1

Answer:

$\large\bold\red{12\:yrs.}$

Step-by-step explanation:

Let,

Present age of Sunitha = x yrs.

Therefore,

Present age of Reena = 2x yrs.

3 years ago,

Age of Sunitha = (x -3) yrs.

Age of Reena = (2x-3) yrs.

But,

According to Question,

Reena was 3 times as old as Sunitha.

Therefore,

We get,

$= > 2x - 3 = 3(x - 3) \\ = > 2x - 3 = 3x - 9 \\ = > 3x - 2x = 9 - 3 \\ = > x = 6$

Therefore,

Present age of Sunitha = 6 yrs.

Hence,

Present age of Reena = 12 yrs.

Answer 2

Given :----

• Reena = 2 × sunitha ..
• 3 years ago , Reena = 3 × sunitha ..

To Find :----

• present age of sunitha ....

$\textsf{we can solve it by 2 methods..}$

$\textsf{see both methods ... }$

_______________________________________

$\pink{\bold{\underline{\underline{Solution(1)}}}}$

$\textbf{Let present age of sunitha = x .}$

Than, present age of Reena = 2x .

3 years ago sunitha was = (x-3) years old ,

3 years ago Reena was = (2x-3) years old .

It is given that, Reena was 3 times of sunitha age 3 years ago,

so, According to Question Now,

$(2x - 3) = 3(x - 3) \\ \\ \implies \: 2x - 3 = 3x - 9 \\ \\ \implies \: - 3 + 9 = 3x - 2x \\ \\ \implies \: x = 6$

So,

Present age of Reena = 2x = 2 × 6 = $\large\red{\boxed{\sf 12\:Years}}$

______________________________

$\red{\bold{\underline{\underline{Solution(2)}}}}$

$\textbf{Lets try it with Ratio Method Now.}$

Ratio of Sunitha and Reena present age = 1 : 2

Ratio of Them 3 years ago = 1 : 3 ..

(1 : 2)×2 = 2 : 4

(1 : 3)×1 = 1 : 3

So, (2 - 1) = (4 - 3) = 3 Years (As it was 3 years ago)

So,

1 unit ------------------------------------------------- 3 years .

4 unit(Reena Present )------------------------- 3×4 = 12 years.

So, Reena Present age is = $\large\green{\boxed{\sf 12\:Years}}$

______________________________

(Hope it helps you)