Question

Reena's age is 3 tims of the age of seema .And the sum of their ages is 64 .Find their ages (solve it with systematic method)

Answer 1

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Answer 2

Hello here is your answer ...

$<b>Let the age of Seema be = x years </b>$

$<b> Reena's age is 3 times more than Seema , so Reena's age be = 3x years </b>$

A/Q

x+3x=64

4x=64

x=64/4

x=16

So,
$<b>Age of Seema = 16 years </b>$

$<b>Age of Reena = 3x ➡ 3(16) ➡ 48 years </b>$

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