Question

Reena's age is 3 tins of the age of seema .And the sum of their ages is 64 .Find their ages (solve it with sistamatic mathod)

Answer 1

Let
The age of Seema be x
=> The age of Reena will be 3x
Sum of their ages is 64
=> x + 3x = 64
=> 4x = 64
=> x = 64/4
=> x = 16
Therefore the age of Seema is 16 and Reema is 48.

Hope this helps!

Answer 2

There u go....
as Reena's age is 3 times of Seema's age , it is necessary that we take Seema's age as X so that Reena's age becomes 3X

Let Seema's age be X.
therefore Reena's age = 3X

sum of their ages = 64
X + 3X = 64
4X = 64
X = 64/4
X= 16
therefore Seema's age is 16 and Reena's age = 3x
=16×3
= 48
hope this helps