Question

Reena's mother is four times as old as Reena. After 5 years, her mother will be three times as
old as she will be then. Find their present ages.​

Answer 1

• Given

• Reena's mother is four times as old as Reena.
• After 5 years her mother's age will be three times Reena's age.

• To find

• Their present ages.

• Solution

Let the present of Reena be x and her mother's age be 4x.

After 5 years,

• Reena's age = (x + 5) years
• Reena's mother's age = (4x + 5) years

According to the question,

⇒ (4x + 5) = 3(x + 5)

⇒ 4x + 5 = 3x + 15

⇒ 4x - 3x = 15 - 5

⇒ x = 10

The value of x = 10

Their present ages -

• Reena's age = x = 10 years
• Reena's mother's age = 4x = 4 × 10 = 40 years

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Answer 2

Step-by-step explanation:

Reena's mother age=4x

Reena age= X

now, five years after ...

reena's mother age = 4X+5

reena's age= X + 5

therefore, 4X + 5= 3 (X+5)

4x =3 x,=10

X= 10

Reena's age =

Reena's mother age = 40