Reena took a loan of rs.1200 with simple interest for as many years as the rate of interest. If she paid rs.432 as interest at the end of the loan period, what was the rate of interest?
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Answer:
Rate of interest is 6%
Explanation:
Formula for Simple Interest is
SI = (P × R × T)/100
where, P = Principal amount, R = Rate of interest, T = Time in years
Given that Reena took a loan of Rs 1200
Thus, we have P = Rs 1200
Also, Rate of interest is equal to number of years loan is taken
Thus, we have R = T
Also, interest paid by Reena is Rs 432
Thus, we have SI = Rs 432
Substituting the values in formula for Simple Interest, we get
432 = (1200 × R × T)/100
Now, R = T
Thus, we get
432 = (1200 × R × R)/100
432 = 12 × R^2
R^2 = 432/12
R^2 = 36
R = ±√36
R = ±6
Now, rate of interest can never be negative
Hence, rate of interest = 6%
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