Question

Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?

Answer 1

Principle= rs 1200
Time= Rate of interest= x (let)
Simple Interest= rs432
Therefore,SI=PTR/100
432=1200×X×X/100
1200x^2=432×100
x^2= 432×100/1200=36
x= √36=6

Answer 2

Answer:

18 or 6

Step-by-step explanation:

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