reena weight 63 kg she reduced her weight in the ratio 9:8 fingers her new weight
Answers
Answered by
70
Hi ,
Reena weight = 63 kg
Let her reduced weight = x
Ratio of the weights = 9 : 8 ( given )
63 : x = 9 : 8
Product of means = product of
extrems
x × 9 = 63 × 8
x = ( 63 × 8 )/9
x = 7 × 8
x = 56
Therefore ,
Her new reduced weight = x = 56kg
I hope this helps you.
: )
Reena weight = 63 kg
Let her reduced weight = x
Ratio of the weights = 9 : 8 ( given )
63 : x = 9 : 8
Product of means = product of
extrems
x × 9 = 63 × 8
x = ( 63 × 8 )/9
x = 7 × 8
x = 56
Therefore ,
Her new reduced weight = x = 56kg
I hope this helps you.
: )
Answered by
25
Let, present weight be x,
Then,
63/x = 9/8
=> (63×8)/9 = x
=> 7 × 8 = x
=> 56 =x
Then,
New weight of reena = 56 kg
I hope this will help you
(-:
Then,
63/x = 9/8
=> (63×8)/9 = x
=> 7 × 8 = x
=> 56 =x
Then,
New weight of reena = 56 kg
I hope this will help you
(-:
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