Math, asked by adityaminhas1358, 10 months ago

Reena went shopping and spent half of what she had on buying fruits. Out of

the money she was left with, she gave H 5 to a beggar. She spent one-third of

the remaining money on rickshaw fare. When she reached home, she found

that she has exactly H 100 left. How much money she initially had? What value

is shown by Reena?​

Answers

Answered by hukam0685
82

Answer:

Reena initially had 310 Rs.

Step-by-step explanation:

let Reena has x rupees in the beginning.

out of those she spend half on fruits.

Money spend on fruits=x/2 rupees

She has left with x/2 rupees

After giving 5 Rs to beggar,

money left with Reena = (x/2-5)Rs

Spend 1/3 on the rickshaw

money left with Reena

 (\frac{x}{2}  - 5) -  \frac{1}{3} (\frac{x}{2}  - 5) \\  \\ =  \frac{2}{3}  (\frac{x}{2}  - 5) \:

Now she has Rs 100,i.e.

 \frac{2}{3} (\frac{x}{2}  - 5) = 100 \\ \\  (\frac{x}{2}  - 5) = 150 \\  \\  \frac{x}{2}  = 155 \\  \\ x = 310 \\  \\

She has 310 Rupees with her.

Reena is kind hearted lady,that's why she gave money to beggar.

*Note: Value based questions are removed from board exams.

Answered by omajaigarh2006
8

Answer:

Reena initially had 310 Rs.

Step-by-step explanation:

let Reena has x rupees in the beginning.

out of those she spend half on fruits.

Money spend on fruits=x/2 rupees

She has left with x/2 rupees

After giving 5 Rs to beggar,

money left with Reena = (x/2-5)Rs

Spend 1/3 on the rickshaw

money left with Reena

\begin{lgathered}(\frac{x}{2} - 5) - \frac{1}{3} (\frac{x}{2} - 5) \\ \\ = \frac{2}{3} (\frac{x}{2} - 5) \:\end{lgathered}

(

2

x

−5)−

3

1

(

2

x

−5)

=

3

2

(

2

x

−5)

Now she has Rs 100,i.e.

\begin{lgathered}\frac{2}{3} (\frac{x}{2} - 5) = 100 \\ \\ (\frac{x}{2} - 5) = 150 \\ \\ \frac{x}{2} = 155 \\ \\ x = 310 \\ \\\end{lgathered}

3

2

(

2

x

−5)=100

(

2

x

−5)=150

2

x

=155

x=310

She has 310 Rupees with her.

Reena is kind hearted lady,that's why she gave money to beggar.

*Note: Value based questions are removed from board exams.

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