Question

REENSHOT PROHIBITED
If full load copper loss in de
generator is 2000 Watt. What would
the copper loss at half full load
condition ?​

Answer 1

Step-by-step explanation:

Copper loss is proportional to square of load current. At half load, load current becomes half as voltage remains same, so copper loss will become

$\frac{1}{2}$

times of full load copper loss or

$\frac{1}{2} × 2000= 1000 \: Watt.$

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Hope it will be Helpful :)

Answer 2

Copper loss is proportional to square of load current. At half load, load current becomes half as voltage remains same, so copper loss will become 1/2.

times of full load copper loss or

1/2× 2000= 1000 Watt.

1/2 ×2000=1000 Watt..

Hope this helps!!!

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