Reenu father age is thrice at reenu after 12 years reenu is twice at reenu find the present ages
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HI
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Reenu father age is thrice at reenu after 12 years reenu is twice at reenu find the present ages
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here is the solution .....................
let reenu be x
her father = 3x
ACQ,after 12 years reenu's father is twice at reenu
so lets form an equation
(12+3x) = 2(12+x)
12 +3x =24+2x
3x-2x = 24-12
x =12
father = 3x
= 12*3
= 36 years
:0
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