Math, asked by Dushyant2524, 1 year ago

Reenu father age is thrice at reenu after 12 years reenu is twice at reenu find the present ages

Answers

Answered by Raghav3333
11

HI

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Reenu father age is thrice at reenu after 12 years reenu is twice at reenu find the present ages

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here is the solution .....................

let reenu be x

her father = 3x

ACQ,after 12 years reenu's father is twice at reenu

so lets form an equation

(12+3x) = 2(12+x)

12 +3x =24+2x

3x-2x = 24-12

x =12

father = 3x

= 12*3

= 36 years

:0



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