Reenu's father is thrice as old as Rennu.After 12 years he will be just twice his daughter. Find their present age
Answers
Answered by
27
Heya mate, Here is ur answer
Let Reenu's age be x years.
Then, Father's age =3x
After 12 years
Reenu's age =x+12
Father's age =3x+12
A/Q
Father's age after 12 years =2(x+12)
3x+12=2(x+12)
3x+12=2x+24
Taking like terms a side
3x-2x=24-12
x=12
So,
Reenu's age=12 years
Father's age=3×12
=36 years
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Let Reenu's age be x years.
Then, Father's age =3x
After 12 years
Reenu's age =x+12
Father's age =3x+12
A/Q
Father's age after 12 years =2(x+12)
3x+12=2(x+12)
3x+12=2x+24
Taking like terms a side
3x-2x=24-12
x=12
So,
Reenu's age=12 years
Father's age=3×12
=36 years
Warm regards
@Laughterqueen
Be Brainly ✌✌✌
Answered by
7
Let the present ages of Reenu be x and Reenu's father be 3x (Reenu's father is thrice as old as Rennu.)
Reenu's age after 12 years: x + 12
After 12 years he will be just twice his daughter: 3x + 12 = 2(x + 12)
3x + 12 = 2x + 24
3x - 2x = 24 - 12
x = 12
Therefore Reenu's age = 12 and Reenu's father's age = 3*12 = 36
Hope it helps :)
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