reeta is eating pani puri at e-seva center the length of her shadow is 3 ft and angle of aviation is 45 degree, then the height of reeta is
Answers
Given :- reeta is eating pani puri at e-seva center the length of her shadow is 3 ft and angle of aviation is 45 degree, then the height of reeta is ?
Answer :-
Let us assume that, height of reeta is x m .
so,
→ tan θ = perpendicular / base .
→ tan θ = height of reeta / shadow of reeta .
→ tan 45° = x / 3
→ 1 = x/3
→ x = 3 ft .(Ans.)
Hence, height of reeta is 3 ft.
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Given : Reeta is eating pani puri at e-seva centre the length of her shadow
is 3ft and angle of elevation is 45°,
To Find : the height of Reeta
1) 3√3ft
2) 3 ft
3) 6ft
4)6√3ft
Solution:
Tan ( angle of elevation ) = Height / Shadow length
angle of elevation= 45°
Height = h ft
Shadow length = 3 ft
Tan 45° = h/3
Tan 45° = 1
=> 1 = h/3
=> 3 = h
=> h = 3
height of Reeta is 3 ft
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