Question

Reeta is eating pani puri at e-seva centre the length of her shadow
is 3ft and angle of elevation is 45°, then the height of Reeta is
1) 3√3ft
2) 3 ft
3) 6ft
4)6√3ft


who answer this are brainlist​

Answer 1

Given : Reeta is eating pani puri at e-seva centre the length of her shadow

is 3ft and angle of elevation is 45°,

To Find : the height of Reeta

1) 3√3ft

2) 3 ft

3) 6ft

4)6√3ft

Solution:

Tan ( angle of elevation )   =  Height /  Shadow length

angle of elevation= 45°

Height  = h   ft

Shadow  length = 3 ft

Tan 45°  = h/3

Tan 45° = 1

=> 1 = h/3

=> 3 = h

=> h = 3

height of Reeta is 3 ft

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Answer 2

Answer:

ans will be 3ft

i hope it will help you